Question

# A ray of light is incident on a 60$$^o$$ prism at the minimum deviation position. The angle of refraction at the first face (i.e., incident face) of the prism is :

A
zero
B
30o
C
45o
D
60o

Solution

## The correct option is B 30$$^o$$Angle of prism, $$A = r_1 + r_2$$For minimum deviation$$r_1 = r_2 = r$$           $$\therefore$$ $$A = 2r$$Given, A = 60$$^o$$Hence,  $$r =\displaystyle \dfrac{A}{2} = \dfrac{60^o}{2} = 30^o$$Physics

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