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Question

A ray of light is incident on a 60$$^o$$ prism at the minimum deviation position. The angle of refraction at the first face (i.e., incident face) of the prism is :


A
zero
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B
30o
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C
45o
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D
60o
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Solution

The correct option is B 30$$^o$$
Angle of prism, $$A = r_1 + r_2$$

For minimum deviation

$$r_1 = r_2 = r$$           $$\therefore$$ $$A = 2r$$

Given, A = 60$$^o$$

Hence,  $$r =\displaystyle \dfrac{A}{2} = \dfrac{60^o}{2} = 30^o$$

287349_306075_ans_6d5f08d0ba5345028ede667ebc88ec52.png

Physics

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