A ray of light is incident on a plane mirror making an angle of 30- with the normal- The angle between reflected ray and the normal for this ray of light will be - a 30- b 60- c 0- d 60-

Required angle will be 30^∘ Because angle of reflection equal to angle of incidence on plane mirror ...

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Standard X

Physics

Laws of Reflection

A ray of ligh...

Question

A ray of light is incident on a plane mirror making an angle of $30^{\circ}$ with the normal. The angle between reflected ray and the normal for this ray of light will be : (a) $30^{\circ}$ (b) $60^{\circ}$ (c) $0^{\circ}$ (d) $60^{\circ}$

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Solution

Required angle will be $30^{\circ}$
Because angle of reflection equal to angle of incidence on plane mirror

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A ray of light is incident on a plane mirror making an angle of 30∘ with the normal. The angle between reflected ray and the normal for this ray of light will be : (a) 30∘ (b) 60∘ (c) 0∘ (d) 60∘

Required angle will be 30∘ Because angle of reflection equal to angle of incidence on plane mirror

A ray of light is incident on a plane mirror making an angle of $30^{\circ}$ with the normal. The angle between reflected ray and the normal for this ray of light will be : (a) $30^{\circ}$ (b) $60^{\circ}$ (c) $0^{\circ}$ (d) $60^{\circ}$

Required angle will be $30^{\circ}$
Because angle of reflection equal to angle of incidence on plane mirror