A ray of light is incident on a transparent glass slab of refractive index 1.62. If the reflected and refracted rays are mutually perpendicular, what is the angle of incidence?
A
tan−1(1.62)
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B
cot−1(1.62)
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C
sin−1(1.62)
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D
cos−1(1.62)
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Solution
The correct option is Atan−1(1.62)
Let the angle of incidence, angle of reflection and angle of refraction be i, r and r', respectively.
Now, as per the question 90 - r + 90 - r' = 90 ⇒ r' = 90 - i(because i = r)
In case of reflection according to Snell's law, 1 sin i = μ sin r'
or sin i = μ sin r' or sin i = μ sin (90 - i) ⇒ tan i = μ or i=tan−1(μ)=tan−1(1.62)=58.3∘