Question

A ray of light is incident on one of the refracting faces of an equilateral prism, at an angle of incidence 48${}^{\circ }$, in the minimum deviation position.Theangle of deviation produced by the prism is

• A. 48${}^{\circ }$
• B. 36${}^{\circ }$
• C. 24${}^{\circ }$
• D. 18${}^{\circ }$

Answer 1

The correct option is B 36${}^{\circ }$

Given,

$i_1={48}^o$

$A={60}^o$

For minimum deviation position,

$2i_1=A+{\delta }_m$

$\therefore 2\times {48}^o={60}^o+{\delta }_m$

$\therefore {\delta }_m={36}^o$

Hence the angle of deviation produced by prism is ${36}^o$.