Question

A ray of light is incident on the plane surface of a transparent medium at an angle 60° with the normal. The angle of refraction is 30°. Calculate the refractive index of the transparent material. Give the equation of refractive index interms of real depth and apparent depth. [3 MARKS]

Answer 1

Formula of refractive Index: 1 Mark
Answer: 1 Mark
Equation: 1 Mark

1. Given
$i={60}^0$

$r={30}^0$

Refractive index = n

$n=\frac{sini}{sinr}=\frac{sin{60}^{\circ }}{sin{30}^{\circ }}=\frac{\sqrt{3}/2}{1/2}=\sqrt{3}$

2. The refractive index of a medium is also given by= $\frac{Realdepth}{Apparentdepth}$.