Question

A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\varphi$. If $\mu$ represents the refractive index of glass with respect to air, then the angle between the reflected and the refracted rays is

• A. 90${}^o$ + $\varphi$
• B. $si{n}^{-1}$( $\mu cos\varphi$)
• C. 90${}^o$
• D. 90 $-si{n}^{-1}$ $\left(\frac{sin\varphi }{\mu }\right)$

Answer 1

Answer: (C)

90${}^o$

When angle of incidence is equal to the Brewster's angle then, the angle between reflected and refracted rays is ${90}^o$