A ray of light is normally incident on one face of an equilateral glass prism. What will be the angle of incidence at the second face of the prism ?

0^{o}

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30^{o}

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60^{o}

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90^{o}

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Solution

The correct option is C $60^{o}$
The ray will not undergo any deviation at the first surface since it is incident normally.
Using external angle theorem,
$∠ A D E + ∠ D A E = ∠ D E C$
$90^{o} + 60^{o} = 90^{o} + r$
$r = 60^{o}$

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A ray of light is normally incident on one face of an equilateral glass prism. What will be the angle of incidence at the second face of the prism ?

The correct option is C 60oThe ray will not undergo any deviation at the first surface since it is incident normally. Using external angle theorem,∠ADE+∠DAE=∠DEC90o+60o=90o+r r=60o

The correct option is C $60^{o}$
The ray will not undergo any deviation at the first surface since it is incident normally.
Using external angle theorem,
$∠ A D E + ∠ D A E = ∠ D E C$
$90^{o} + 60^{o} = 90^{o} + r$
$r = 60^{o}$