A ray of light is sent along the line x + y = 1, after being reflected from the line y ā x = 1 it is again reflected from the line y = 0, then the equation of the line representing the ray after second reflection may be given as
A
x + y = 1
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B
x – y = 1
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C
y – x = 1
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D
x + y + 1 = 0
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Solution
The correct option is Bx – y = 1 Since, incident ray is perpendicular to the line mirror y - x = 1, so after reflection reflected ray goes back and intersect x-axis at A.