A ray of light moving parallel to x−axis gets reflected from the parabolic mirror whose equation is given by y2−10y−8x+41=0 After reflection, the ray must passes through the point
A
(4,5)
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B
(−4,−5)
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C
(−4,5)
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D
(4,−5)
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Solution
The correct option is C(4,5) As y2−10y−8x+41=0 ⇒(y−5)2=8(x−2) ⇒Y2=8X=4(2)X Where Y=y−5,X=x−2 ⇒ focus (X,Y)=(2,0) ⇒x−2=2,y−5=0 ⇒x=4,y=5 ∴ After reflection, the ray must pass through the focus (4,5) Hence choice (a) is correct answer