Question

A ray of light on a glass water interface at an angle of $37°$. The refractive index of water is 4/3. If the refracted rays makes an angle of $30°$ with the normal. What is the refractive index of glass?

Answer 1

Dear Student,


$$\begin{gathered} \frac{\sin i}{\sin r}=\frac{{\mu }_g}{4/3} \\ \frac{{\displaystyle \sin 37}}{{\displaystyle \sin 30}}=\frac{{\displaystyle {\mu }_g}}{{\displaystyle 4/3}} \\ \frac{{\displaystyle 3/5}}{{\displaystyle 1/2}}=\frac{{\displaystyle {\mu }_g}}{{\displaystyle 4/3}} \\ {\mu }_g=\frac{4}{3}\times \frac{6}{5}=\frac{8}{5}refractiveindexofglass \\ Regards \end{gathered}$$