A ray of light passes normally through a slab (μ=1.5) of thickness ′t′. If the speed of light in vacuum be ′c′ then time taken by the ray to go across the slap will be
A
tc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3t2c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2t3c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4t9c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B3t2c η=cv⇒v=c1.5=2c3time=3t2cHence,optionBiscorrectanswer.