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Question

A ray of light passes through a prism whose refracting angle is 5o and dispersive power is 0.03. The refractive index for the mean ray in a spectrum is 1.62. The mean deviation and angle of dispersion respectively are

A
3.1o,0.077o
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B
3.1o,0.093o
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C
6.2o,0.093
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D
6.2o,0.077o
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Solution

The correct option is C 3.1o,0.093o
DISPERSION OF LIGHT:
For a thin prism with apex angle A and refractive index μ, the deviation produced is 
d=(μ1)A

The ratio of angular dispersion for two extreme&nbsp;colours to their mean deviation is called&nbsp;<span>dispersive power of prism ( ω ) Dispersive power = ( ω ) = Angulardispersionmeandeviation.

Dispersive power does not depend upon the angle&nbsp;of prism. It only depends upon material.

Mean deviation is given by

d=(μ1)A=(1.621)5=3.1

Using formula for dispersive power we can find angle of dispersion:

Dispersivepower=Angular dispersionMean deviation

0.03=ϕ3.1

ϕ=3.1×0.03=0.093.

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