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Byju's Answer
Standard XII
Physics
Minimum Deviation
A ray of ligh...
Question
A ray of light passing through a prism having
μ
=
√
2
suffer minimum deviation. It is found that angle of incidence is double the angle of refraction within the prism. Find angle of the prism.
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Solution
if
∠
i
=
incidence angle
∠
r
=
refracted angle
∠
i
=
2
×
∠
r
sin
i
sin
r
=
μ
sin
2
r
sin
r
=
2
sin
r
cos
r
sin
r
=
2
cos
r
=
√
2
cos
r
=
1
√
2
r
=
45
∘
For minimum deviation,
r
1
=
r
2
=
r
∴
a
=
2
×
r
∠
a
=
2
×
45
∘
=
90
∘
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