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Question

A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 as shown in the figure. If the angle of incidence of ray is θ, the value of θ is
475981.png

A
sin1(89)
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B
sin1(1318)
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C
sin1(1316)
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D
sin1(813)
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Solution

The correct option is D sin1(1316)
Applying Snell's Law at interface 2:
μ3μ2=sin(θc)......(i)

Using equality of alternate angles,
θ2=θc

Applying Snell's Law at interface 1:
μ2μ1=sin(θ)sin(θc)..........(ii)

From (i) and (ii), sin(θ)=μ3μ1=1.31.6=1316
θ=sin1(1316)

511886_475981_ans.png

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