A ray of light strikes a transparent rectangular slab of refractive index √2 at an angle of incidence of 45∘. The angle between the reflected and refracted rays is :
A
750
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B
900
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C
1050
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D
1200
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Solution
The correct option is C1050 Given:
Angle of incident, i=45∘
refractive index, μ=√2
From snell's Law:
The angle of insident=Angle of reflection i=r=45∘
For refraction,
sinisinr2=√2
sin45sinr2=√2
⇒r2=30∘
Now, from figure angle between refracted and reflected ray is 45+60=105∘