A ray of light traveling in air falls on the surface of water. The angle of incidence is $60^{0}$ with the normal to the surface. The refractive index of water = $\frac{4}{3}$ . Calculate the angle of refraction. [2 MARKS]

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Solution

Formula: 1 Mark
Answer: 1 Mark
Given:
$i = 60^{0}, n = \frac{4}{3}$

We know
$\frac{sin i}{sin r} = n$

$\frac{s i n 60^{o}}{sin r}$ = $\frac{4}{3}$

$s i n r = 0.649$

$r = {40.5}^{0}$

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