Question

A ray of light travelling from medium I in which speed of light is $2\times {10}^{8}m/s$ to a medium II in which speed of light is $1.5\times {10}^{8}m/s$. Choose the correct ray diagram:

I. $u=2\times {10}^{8}m/s$

II. $v=1.5\times {10}^{8}m/s$

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

The speed of light is inversely proportional to the refractive index of the medium.
Given, the speed of light in medium I = $u=2\times {10}^{8}m/s$
The speed of light in medium II = $v=1.5\times {10}^{8}m/s$
Since $u>v$, so medium I is optically rarer medium than medium II.
When a ray of light passes from rarer to a denser medium it bends towards normal.