A ray of light travelling in the air falls on the surface of a glass slab at an angle $45^{\circ}$ with the normal. The refractive index of glass is 1.5. Calculate the angle of refraction.

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Solution

Angle of incidence = $45^{\circ}$

Refractive index of glass = n = 1.5

n = $\frac{sin i}{sin r}$

sin r = $\frac{sin 45^{\circ}}{1.5}$ = 0.4728

r = $28^{\circ}$

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A ray of light travelling in the air falls on the surface of a glass slab at an angle 45∘ with the normal. The refractive index of glass is 1.5. Calculate the angle of refraction.

Angle of incidence = 45∘ Refractive index of glass = n = 1.5 n = sinisinr sin r = sin 45∘1.5 = 0.4728 r = 28∘

A ray of light travelling in the air falls on the surface of a glass slab at an angle $45^{\circ}$ with the normal. The refractive index of glass is 1.5. Calculate the angle of refraction.

Angle of incidence = $45^{\circ}$

Refractive index of glass = n = 1.5

n = $\frac{sin i}{sin r}$

sin r = $\frac{sin 45^{\circ}}{1.5}$ = 0.4728

r = $28^{\circ}$