A ray of light travelling in water is incident on its surface open to air. The angle of incidence θ, which is less than the critical angle. Then there will be:
A
only a reflected ray and no refracted ray
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B
only a refracted ray and no reflected ray
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C
a reflected ray and a refracted ray and the angle between them would be less than 180o−2θ
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D
a reflected ray and a refracted ray and the angle between them would be greater than 180o−2θ
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Solution
The correct option is B a reflected ray and a refracted ray and the angle between them would be less than 180o−2θ
As θ is less than critical angle, some portion of the light is reflected and some are refracted.
Clearly from the diagram, 2θ+8+α=180°
⇒8=(180°−2θ)−α
8<(180°−2θ).
Hence, the answer is a reflected ray and a refracted ray and the angle between them would be less than 180°−2θ.