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Physics

Refractive Index of a Prism

A ray of ligh...

Question

A ray of light travelling inside a rectangular glass block of refractive index $\sqrt{2}$ is incident on the glass-air surface at an angle of incidence of $45$ . Show that the ray will emerge into the air at an angle of refraction equal to $90$ .

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Solution

Given, $C = 45$
$sin C = \frac{1}{μ} = \frac{1}{\sqrt{2}} = sin 45$
So, the ray will graze the interface after refraction at an angle of $90$

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A ray of light travelling inside a rectangular glass block of refractive index √2 is incident on the glass-air surface at an angle of incidence of 45. Show that the ray will emerge into the air at an angle of refraction equal to 90.

Given, C=45sinC=1μ=1√2=sin45So, the ray will graze the interface after refraction at an angle of 90

A ray of light travelling inside a rectangular glass block of refractive index $\sqrt{2}$ is incident on the glass-air surface at an angle of incidence of $45$ . Show that the ray will emerge into the air at an angle of refraction equal to $90$ .

Given, $C = 45$
$sin C = \frac{1}{μ} = \frac{1}{\sqrt{2}} = sin 45$
So, the ray will graze the interface after refraction at an angle of $90$