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Question

A ray of light travels from air into a perspex block of refractive index 1.5 at an angle of incidence of 450. Calculate the angle of the refraction of the ray at air-to perspex boundary and at perpex-to-air boundary.

A
2807
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B
25087
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C
2507
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D
28027
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Solution

The correct option is A 2807
μperspex=1.5=sinx0sinr

and i=450

sin450sinr=1.5

sinr=12×1.5

r=2807

The angle of refraction of the ray at air to perpex is 2807.

The angle of refraction at perpex to air boundary is angle of incident at air to perpex boundary i.e., 450.

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