A ray of light undergoes deviation of 30∘ when incident on an equilateral prism of refractive index √2. The angle made by the ray inside the prism with the base of the prism is
A
15∘
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B
0∘
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C
45∘
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D
30∘
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Solution
The correct option is B0∘ μ=√2,A=60∘,δ=30∘ For the minimum deviation μ=sin(A+δm2)sin(A2) Substituting the values of A and μ we see that δm=30∘ i.e., the given deviation δm. At minimum deviation the ray inside the prism is parallel to the base in case of an equilateral prism.