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Question

A ray of light undergoes deviation of 30 when incident on an equilateral prism of refractive index 2. The angle made by the ray inside the prism with the base of the prism is

A
15
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B
0
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C
45
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D
30
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Solution

The correct option is B 0
μ=2,A=60,δ=30
For the minimum deviation
μ=sin(A+δm2)sin(A2)
Substituting the values of A and μ we see that δm=30
i.e., the given deviation δm. At minimum deviation the ray inside the prism is parallel to the base in case of an equilateral prism.

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