A ray of monochromatic light follows the path shown in the figure as it passes through five layers of different optical media of refractive indices - 0- 1- 2- 3 and - 4- If the angle of incidence in the first medium is 30-i compare the refractive indices of the media-ii determine the angle of deviation on the whole-

(1) At each interference ,the ray deviate away from the normal.Therefore μ_0 lt; μ_1 lt; μ_2 lt; μ_3 lt; μ_4 (2) At the interference of medium 3 an ...

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Standard XII

Physics

Lateral Displacement

A ray of mono...

Question

A ray of monochromatic light follows the path shown in the figure as it passes through five layers of different optical media of refractive indices $μ_{0}, μ_{1}, μ_{2}, μ_{3}$ and $μ_{4}$ . If the angle of incidence in the first medium is $30^{\circ}$ ,
(i) compare the refractive indices of the media.
(ii) determine the angle of deviation on the whole.

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Solution

(1) At each interference ,the ray deviate away from the normal.
Therefore $μ_{0} < μ_{1} < μ_{2} < μ_{3} < μ_{4}$
(2) At the interference of medium 3 and 4,total internal reflection takes place.
Angle of deviation in the case of reflection $= 180 - 2 i = 180 - 60 = 120^{\circ}$

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(1) At each interference ,the ray deviate away from the normal.Therefore μ0<μ1<μ2<μ3<μ4(2) At the interference of medium 3 and 4,total internal reflection takes place.Angle of deviation in the case of reflection=180−2i=180−60=120∘

(1) At each interference ,the ray deviate away from the normal.
Therefore $μ_{0} < μ_{1} < μ_{2} < μ_{3} < μ_{4}$
(2) At the interference of medium 3 and 4,total internal reflection takes place.
Angle of deviation in the case of reflection $= 180 - 2 i = 180 - 60 = 120^{\circ}$