A ray PO is incident on the mirror AC at an angle 30∘ as shown in the figure Ray PO is reflected by mirror AB and AC the deviation of ray PO after its final reflection from mirror AC is Kπ Find the value of K
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Solution
Given : i=30o
Using i=r, we get r=∠MON=30o
As OM is a normal, thus ∠MOA=90o⟹∠NOA=90o−30o=60o
Hence triangle ONA is a right angled triangle as shown in the figure.
From figure, a ray after being reflected from mirror AC falls normally on mirror
AB and hence bounce back tracing its original path. So the ray is finally