A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $300^{0}$ . The number of observable image is :

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Solution

The correct option is C 11
We know, $O = 360 ° - 2 θ$
$300 ° = 360 ° - 2 θ$
$θ = 30 °$
No. of images formed is
$n = (\frac{360 °}{θ}) - 1$
$n = (\frac{360 °}{30} °) - 1$
$n = 11$
No. of images formed $= 11$

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A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of 3000. The number of observable image is :

The correct option is C 11We know, O=360°−2θ300°=360°−2θθ=30°No. of images formed is n=(360°θ)−1n=(360°30°)−1n=11No. of images formed =11

A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $300^{0}$ . The number of observable image is :

The correct option is C 11
We know, $O = 360 ° - 2 θ$
$300 ° = 360 ° - 2 θ$
$θ = 30 °$
No. of images formed is
$n = (\frac{360 °}{θ}) - 1$
$n = (\frac{360 °}{30} °) - 1$
$n = 11$
No. of images formed $= 11$