A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $240^{o}$ . Then, the number of images observable is?

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Solution

The correct option is A $5$
Deviation, $D = 360^{o} - 2 θ \Rightarrow 240^{o} = 360^{o} - 2 θ$

$2 θ = 120^{o},$ $∴ θ = 60^{o}$

Then, number of images observable:

$N = \frac{360^{o}}{60^{o}} - 1$

$N = 6 - 1$

$N = 5$ .

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A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of 240o. Then, the number of images observable is?

The correct option is A 5Deviation, D=360o−2θ⇒240o=360o−2θ2θ=120o, ∴θ=60oThen, number of images observable:N=360o60o−1N=6−1N=5.

A ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $240^{o}$ . Then, the number of images observable is?

The correct option is A $5$
Deviation, $D = 360^{o} - 2 θ \Rightarrow 240^{o} = 360^{o} - 2 θ$

$2 θ = 120^{o},$ $∴ θ = 60^{o}$

Then, number of images observable:

$N = \frac{360^{o}}{60^{o}} - 1$

$N = 6 - 1$

$N = 5$ .