Question

A RC circuit is connected as shown in the figure. After steady state, the current in the $2\Omega$ resistor is :

• A. $0$
• B. $10A$
• C. $8A$
• D. $2A$
• E. $1A$

Answer 1

Answer: (E)

$1A$

When a capacitor reaches a steady state there is no potential drop across it and hence there is no current flow in that branch of the circuit.

Therefore the total current in the circuit flows through the resistor $2\Omega$ and $8\Omega$. The equivalent resistance in that branch is $R=10\Omega$ and the voltage is $V=10V$

Therefore the current in the branch is $I=\frac{V}{R}=\frac{10V}{10\Omega }=1A$

Option E is correct.