A RC series circuit of R=15Ω and C=10μF is connected to 20 volt DC supply for very long time. Then capacitor is disconnected from circuit and connected to inductor of 10mH. Find amplitude of current.
A
0.2√10A
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B
2√10A
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C
0.2A
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D
√10A
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Solution
The correct option is A0.2√10A Given : C=10μFVo=20 volts L=10mH Amplitude of the current Io=Qow=(CVo)1√LC=√CLVo ⟹Io=√10×10−6010×10−3×20=0.2√10A