MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Rate of Reaction

A reactant A ...

Question

A reactant (A) forms two products:
$A k_{1} - \to B, Activation energy E a_{1}$
$A k_{2} - \to C, Activation energy E a_{2}$
If $E a_{2} = 2 E a_{1}$ , then $k_{1}$ and $k_{2}$ are related as:

A

k_{2} = k_{1} e^{E a_{1} / R T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

k_{2} = k_{1} e^{E a_{2} / R T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

k_{1} = \frac{A_{1}}{A_{2}} k_{2} e^{E a_{1} / R T}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

k_{1} = 2 k_{2} e^{E a_{2} / R T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $k_{1} = \frac{A_{1}}{A_{2}} k_{2} e^{E a_{1} / R T}$
According to the Arrhenius equation,
$k_{1} = A_{1} e^{- E a_{1} / R T} . . . (i)$
$k_{2} = A_{2} e^{- E a_{2} / R T} . . . (i i)$
On dividing eq. $(i)$ from $(i i)$
$\frac{k_{1}}{k_{2}} = \frac{A_{1}}{A_{2}} e^{(E a_{2} - E a_{1}) / R T} . . . (i i i)$
Given: $E a_{2} = 2 E a_{1}$
On substituting this value in eq. (iii), we get
$k_{1} = \frac{A_{1}}{A_{2}} k_{2} e^{E a_{1} / R T}$

Suggest Corrections

thumbs-up

8

Similar questions

Q. A reactant (A) forms two products.

A k_{1} - \to B

, Activation energy

E a_{1}

A k_{2} - \to C

, Activation energy

E a_{2}

E a_{2} = 2 E a_{1}

k_{1}

k_{2}

are related as:

(A)

forms two products:

A k_{1} - ---- \to B

, Activation energy

E_{a_{1}}

and Pre-exponential factor

A

A k_{2} - ---- \to C

, Activation energy

E_{a_{2}}

and Pre-exponential factor

A

E_{a_{2}} = 2 E_{a_{1}}

k_{1}

k_{2}

will be related as:

A_{1}

B, Activation Energy

E a_{1}

A_{2}

C, Activation Energy

E a_{2}

E a_{2} = 2 E a_{1}

k_{1}

k_{2}

are related as:

Q. For two reactions, activation energies are

E_{a_{1}}

E_{a_{2}}

; rate constants are

k_{1}

k_{2}

at the same temperature. If

k_{1} > k_{2}

Q. For reaction;

A \to B

, the rate of constant

k_{1} = A_{1} e^{- E a_{1} / R T}

and for the reaction;

P \to Q

, the rate constant

k_{2} = A_{2} e^{- E a_{2} / R T}

A_{1} = 10^{8}, A_{2} = 10^{10}

E a_{1} = 600, E a_{2} = 1200

, then the temperature at which

k_{1} = k_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Rate of Reaction

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Rate of Reaction

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon