A reaction A 2- B 2- 2 AB occurs by the following mechanism A 2- A - A - - - slow A - B 2- AB - B - - fast A - B - AB -fastIts order would be A- 3-2B- 1C- 2D- zero

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Types of Equillibrium

A reaction A ...

Question

A reaction $A_{2} + B_{2} \to 2 A B$ occurs by the following mechanism
$A_{2} \to A + A$ .....(slow)
$A + B_{2} \to A B + B$ .....(fast)
$A + B \to A B$ ...(fast)
Its order would be

\frac{3}{2}

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zero

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A_{2} + B_{2} \to 2 A B

A \to A + A . . .

A + B_{2} \to A B + B . . .

\to

A_{2} + B_{2} \to 2 A B

A_{2} ⇌ A + A

A + B_{2} \to A B + B

\to

A_{2} + B_{2} \to 2 A B

A_{2} \Leftrightarrow A + A (f a s t)

A + B_{2} \to A B + B (s l o w)

A + B \to A B (f a s t)

A_{2} + B_{2} ⟶ 2 A B

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A + B_{2} ⟶ A B + B

A + B ⟶ A B

A_{2} + B_{2} \to 2 A B

A_{2} ⇌ A + A (fast)

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