A reaction gives the following result:

What would be the percentage of back side attack of the reagent assuming the reaction is completed?

35%

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85%

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65%

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30%

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Solution

The correct option is C 65%

70% racemisation will be due to $S_{N} 1$ pathway, in which 35% will constitute the back side attack. 30% back side attack would be due to $S_{N} 2$ reaction. So total back side attack = 35 + 30 = 65%

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A reaction gives the following result: What would be the percentage of back side attack of the reagent assuming the reaction is completed?

The correct option is C 65% 70% racemisation will be due to SN1 pathway, in which 35% will constitute the back side attack. 30% back side attack would be due to SN2 reaction. So total back side attack = 35 + 30 = 65%

A reaction gives the following result:

What would be the percentage of back side attack of the reagent assuming the reaction is completed?

The correct option is C 65%

70% racemisation will be due to $S_{N} 1$ pathway, in which 35% will constitute the back side attack. 30% back side attack would be due to $S_{N} 2$ reaction. So total back side attack = 35 + 30 = 65%