Question

A reaction has an activation energy of $209kJ.mo{l}^{-1}$. The rate increases $10$ - fold when the temperature is increased from ${27}^o$C to $X^{o}C$. The temperature X is closest to.[Gas constant, $R=8.314$ $J.mo{l}^{-1}{K}^{-1}$].

• A. $35$
• B. $40$
• C. $30$
• D. $45$

Answer 1

Answer: (A)

$35$

We know,

$\ln \frac{k_2}{k_1}=-\frac{E_a}{R}(\frac{1}{T_2}-\frac{1}{T_1})$

$\ln \frac{10}{1}=-\frac{209000}{8.314}(\frac{1}{X}-\frac{1}{300})$

Solving the equation we get,

$X=308K={35}^{o}C$.