CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A reaction is first order in A and second order in B:

Write the differential rate equation.

How is the rate affected on increasing the concentration of B three times?

How is the rate affected when the concentrations of both A and B are doubled?


Solution

Rate =k[A][B]2

Rate =k[A][3B]2=9k[A][B]2 Rate of reaction becomes 9 times

Rate =k[2A][2B]2=8k[A][B]2 Rate of reaction becomes 8 times.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


Same exercise questions
View More



footer-image