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Question

A reaction is first order in A and second order in B:

Write the differential rate equation.

How is the rate affected on increasing the concentration of B three times?

How is the rate affected when the concentrations of both A and B are doubled?

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Solution

Rate =k[A][B]2

Rate =k[A][3B]2=9k[A][B]2 Rate of reaction becomes 9 times

Rate =k[2A][2B]2=8k[A][B]2 Rate of reaction becomes 8 times.


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