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B
both ΔH and ΔS are -ve
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C
ΔH is -ve and ΔS is +ve
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D
none of these
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Solution
The correct option is AΔH is +ve, ΔS is -ve For any reaction to be non-spontaneous the value of change in Gibb's free energy should be positive. Since, ΔG=ΔH−TΔS So, the value of ΔG>0i.e.value of ΔH>0 and value of ΔS<0 Hence, answer is option A.