A reaction is second order with respect to a reactant. If the concentration of reactant is doubled the rate of reaction becomes :

doubled

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halved

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four times

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remains same

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Solution

The correct option is C four times
If the concentration of reactant is doubled the rate of reaction becomes :

$r a t e = k [A]^{2}$

$r a t e_{1} = k [2 A]^{2} = 4 r a t e$

So, the correct option is $C$

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A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reaction is

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