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Byju's Answer
Standard XII
Chemistry
Activation Energy
A reaction oc...
Question
A reaction occurs in 3 steps having rate constant
K
1
,
K
2
,
K
3
the overall rate constant of the reaction
1
△
K
=
K
1
K
2
K
3
The
E
a
energies of first, second and third steps are 30, 60, 40
k
J
m
o
l
−
1
respectively. Determine activation energy of the reaction.
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Solution
R
1
=
A
1
e
−
E
a
1
/
R
T
=
A
1
e
−
30
K
J
/
R
T
R
2
=
A
2
e
−
E
o
R
J
/
R
T
R
3
=
A
3
e
−
40
K
J
/
R
J
K
3
=
A
3
e
−
40
K
J
/
R
J
K
=
K
1
K
2
K
=
A
1
e
−
30
K
J
/
R
T
×
A
2
e
−
60
K
J
/
R
T
A
3
e
−
40
K
J
/
R
T
=
(
A
1
A
2
A
3
)
e
−
50
K
J
/
R
T
∴
E
n
e
t
=
50
R
J
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Similar questions
Q.
A reaction takes place in three steps having rate constants
K
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,
K
2
,
K
3
respectively. The overall rate constant
K
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. If energies of activation for the three steps 40, 30, 20 kJ respectively, the overall energy of activation is:
Q.
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takes place in various steps. The rate constant for first, second, third and fifth steps are
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For a reaction taking place in three steps, the rate constants are
k
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2
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k
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Q.
A reaction takes place in three steps with the rate constant
k
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2
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