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Reactions of Aryl Amines (Diazo Salts)

A reaction of...

Question

A reaction of 0.1 mole of Benzyl amine with bromomethane gave $23 g$ of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times 10^{- 1}$ , when n =_____
. (Round off to the Nearest Integer). [Given: Atomic masses: C: 12.0 u, H : 1.0 u, N : 14.0 u, Br : 80.0 u]

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Solution

Answer: (3)
The given reaction is,
$P h - C H_{2} N H_{2} 0.1 m o l + 3 C H_{3} B r \to P h C H_{2} N^{+} (M e)_{3} B r^{-} 23 g$
$Moles of benzyltrimethylammonium bromide = 23 / 230 = 0.1 m o l$
$∴ moles of C H_{3} B r = 0.3 m o l = 3 \times 10^{- 1} mol$

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Reactions of Aryl Amines (Diazo Salts)

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