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Question

A reaction system in equilibrium according to the equation 2SO2+O22SO3 in 1 litre reaction vessel at a given temperature was found to contain 0.11 mol of SO2, 0.12 of SO3 and 0.05 mol of O2. Another 1 litre reaction vessel contains 64 g of SO2 at the same temperature. What mass of O2 must be added to this vessel in order that at equilibrium half of SO2is oxidised to SO3?

A
9.34 g
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B
10.87 g
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C
21.3 g
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D
32.4 g
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Solution

The correct option is A 9.34 g
2SO2+O22SO3
Kc=0.12×0.12/0.11×0.11×0.05=23.8
Now,
2SO2+O22SO3
2SO2 O2$ 2SO3
6464=12x ax2x=0.5
So mass of oxygen added 0.52/(0.5×0.5×(a0.25))=23.8
ax=0.04
a=0.29
Mass of oxygen added =0.29×32=9.34.

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