A reaction takes place in three steps having rate constants K 1- K 2- K 3 respectively- The overall rate constant K- K 1 K 3 K 2- If energies of activation for the three steps 40- 30- 20 kJ respectively- the overall energy of activation is-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Rate Constant

A reaction ta...

Question

A reaction takes place in three steps having rate constants $K_{1}$ , $K_{2}$ , $K_{3}$ respectively. The overall rate constant $K = \frac{K_{1} K_{3}}{K_{2}}$ . If energies of activation for the three steps 40, 30, 20 kJ respectively, the overall energy of activation is:

Open in App

Solution

$K = A e^{- E a / R T}$
$\Rightarrow \frac{K_{1} K_{3}}{K_{2}} = A e^{- \frac{(E_{a_{1}} + E_{a_{3}} - E_{a_{2}})}{R T}}$
Overall energy of activation is given by,
$∴ E_{a} = E_{a_{1}} + E_{a_{3}} - E_{a_{2}}$
$= 40 + 20 - 30$
$= 30 k J$

Suggest Corrections

Similar questions

A reaction takes place in three steps. The rate constant of the three steps are $k_{1}, k_{2}$ and $k_{3}$ respectively. The overall rate constant $k = \frac{k_{1} k_{3}}{k_{2}} .$ The energy of activation for the three steps are 40, 30 and 20 kJ respectively. Therefore: