A reaction takes place in three steps- The rate constants are k1-k2 and k3- The over all rate constant k - k1k3-k2- If energy of activation E1-E2 and E3 are 60-30 and 10 kJ- The overall energy of activation is-

The correct option is A 40 As we know, k = Ae^ Ea/RT ∴ Ae^ Ea/RT = Ae^ ε_1 ε_3+ε_2/RT ε_a = E_1+E_3 E_2 = 60+10 30 = 40 kJ ...

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Byju's Answer

Standard XII

Chemistry

Arrhenius Equation

A reaction ta...

Question

A reaction takes place in three steps. The rate constants are $k_{1}, k_{2} a n d k_{3} .$ The over all rate constant
$k = \frac{k_{1} k_{3}}{k_{2}} .$ If $(e n e r g y o f a c t i v a t i o n) E_{1}, E_{2} a n d E_{3} a r e 60, 30 a n d 10 k J .$
The overall energy of activation is:

40

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30

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400

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60

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Solution

The correct option is A $40$
As we know,
$k = A e^{- E a / R T}$
$∴ A e^{- E a / R T} = A e^{\frac{- ε_{1} - ε_{3} + ε_{2}}{R T}}$
$ε_{a} = E_{1} + E_{3} - E_{2} = 60 + 10 - 30 = 40 k J$

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A reaction takes place in three steps. The rate constants are k1,k2andk3. The over all rate constantk=k1k3k2. If (energyofactivation)E1,E2andE3are60,30and10kJ. The overall energy of activation is:

The correct option is A 40As we know,k=Ae−Ea/RT∴Ae−Ea/RT=Ae−ε1−ε3+ε2RTεa=E1+E3−E2=60+10−30=40kJ

A reaction takes place in three steps. The rate constants are $k_{1}, k_{2} a n d k_{3} .$ The over all rate constant
$k = \frac{k_{1} k_{3}}{k_{2}} .$ If $(e n e r g y o f a c t i v a t i o n) E_{1}, E_{2} a n d E_{3} a r e 60, 30 a n d 10 k J .$
The overall energy of activation is:

The correct option is A $40$
As we know,
$k = A e^{- E a / R T}$
$∴ A e^{- E a / R T} = A e^{\frac{- ε_{1} - ε_{3} + ε_{2}}{R T}}$
$ε_{a} = E_{1} + E_{3} - E_{2} = 60 + 10 - 30 = 40 k J$