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Question

A reaction takes place in various steps. The rate constant for first, second, third and fifth steps are k1,k2,k3 and k5 respectively. The overall rate constant is given by
k=k2k3(k1k5)1/2, if activation energy are 40,60,50 and 10 kJ/mol respectively, the overall energy of activation (kJ/mol) is:

A
10
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B
20
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C
25
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D
none of these
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Solution

The correct option is D 25
As we know,
k=AeEa/RT

lnk=lnAEaRT

So, according to given value of k, overall energy of activation, Ea=E2E3+12×(E1E5)=6050+(12)×40(12)×10=25 kJ/mol

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