A reaction A2-B2-2AB occurs by the following mechanismA2-A -A slowA - B2 -AB - B fastA- B-AB fastThe order of reaction would be

Slowest step is A_2→A + A (slow) nbsp; Hence, nbsp;r = k[A]_2 Therefore, nbsp;Order = 1 ...

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Elementary and Complex Reactions

A reaction A2...

Question

A reaction $A_{2} + B_{2} \to 2AB$ occurs by the following mechanism

$A_{2} \to A +A (slow) {A + B}_{2} \to AB + B (fast) A+ B \to AB (fast)$

The order of reaction would be

\frac{3}{2}

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