A reaction time for an automobile driver is $0.7 s e c .$ If the automobile can be declared at $5 m / s^{2}$ calculate the total distance travelled in coming to stop from an initial velocity of $8.33 m / s$ after a signal is observed.

12.77 m

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14.82 m

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16.83 m

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19.65 m

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Solution

The correct option is C $12.77 m$
$a = - 5 m / s^{2}$
$u = 8.33 m / s$
v=o
$v^{2} = u^{2} + 2 a s$
$o = {(8.33)}^{2} - 105$

$\Rightarrow \frac{{(8.33)}^{2}}{10} = s = 6.93$
distance in react time
$= 0.7 \times 8.33$
$= 5.831$
total $= 12.769$
$= 12.77$

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A reaction time for an automobile driver is 0.7sec. If the automobile can be declared at 5m/s2 calculate the total distance travelled in coming to stop from an initial velocity of 8.33m/s after a signal is observed.

The correct option is C 12.77ma=−5m/s2u=8.33m/sv=ov2=u2+2aso=(8.33)2−105⇒(8.33)210=s=6.93distance in react time =0.7×8.33=5.831total =12.769=12.77

A reaction time for an automobile driver is $0.7 s e c .$ If the automobile can be declared at $5 m / s^{2}$ calculate the total distance travelled in coming to stop from an initial velocity of $8.33 m / s$ after a signal is observed.

The correct option is C $12.77 m$
$a = - 5 m / s^{2}$
$u = 8.33 m / s$
v=o
$v^{2} = u^{2} + 2 a s$
$o = {(8.33)}^{2} - 105$

$\Rightarrow \frac{{(8.33)}^{2}}{10} = s = 6.93$
distance in react time
$= 0.7 \times 8.33$
$= 5.831$
total $= 12.769$
$= 12.77$