A reactor is generating energy at the rate of 1500 kW. How many atoms of U235 undergo fission per second, if 180 MeV energy is released per fission?
Number of atoms undergoing fission per second = 1.5×106 Js−12.88×10−11 J/atom
=0.521×1017 atoms/sec
=5.21×1016 atoms/sec