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Question

A reactor is generating energy at the rate of 1500 kW. How many atoms of U235 undergo fission per second, if 180 MeV energy is released per fission?


A
6.5×1022
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B
5.2×1016
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C
1.3×1021
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D
2.6×1016
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Solution

The correct option is B 5.2×1016
Rate of generation of energy by the reactor =1500 kW=1.5×106 Js1

Energy released per fission = 180 MeV = 180×106 eV = 180×106×1.6×1019 J/atom = 2.88×1011 J/atom

Number of atoms undergoing fission per second = 1.5×106 Js12.88×1011 J/atom
=0.521×1017 atoms/sec
=5.21×1016 atoms/sec


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