wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

A reactor is generating energy at the rate of 1500 kW. How many atoms of U235 undergo fission per second, if 180 MeV energy is released per fission?


A
6.5×1022
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5.2×1016
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.3×1021
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.6×1016
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5.2×1016
Rate of generation of energy by the reactor =1500 kW=1.5×106 Js1

Energy released per fission = 180 MeV = 180×106 eV = 180×106×1.6×1019 J/atom = 2.88×1011 J/atom

Number of atoms undergoing fission per second = 1.5×106 Js12.88×1011 J/atom
=0.521×1017 atoms/sec
=5.21×1016 atoms/sec


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nuclear Fission
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon