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Iron II Sulphate

A reagent tha...

Question

A reagent that can detect any of ${C u}^{2 +}, {F e}^{3 +}, {Z n}^{2 +}$ and ${C d}^{2 +}$ is $K_{4} [{F e (C N)}_{6}]$ .

If the given statement is true enter 1 else enter 0.

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Solution

A reagent that can detect any of ${C u}^{2 +}, {F e}^{3 +}, {Z n}^{2 +}$ and ${C d}^{2 +}$ is potassium ferrocyanide $K_{4} [{F e (C N)}_{6}]$ .
Fe(III) ions give deep blue colour with potassium ferrocyanide.
$3 K_{4} [F e (C N)_{6}] + 4 F e C l_{3} \to F e_{4} [F e (C N)_{6}]_{3} p u r s s i a n, s b l u + 12 K C l$
Potassium ferrocyanide reacts with Zn(II) ions to form bluish white precipitate of $Z n_{2} [F e (C N)_{6}]$ .
Potassium ferrocyanide reacts with Cd(II) ions to form bluish white precipitate of $C d_{2} [F e (C N)_{6}]$ .
Potassium ferrocyanide reacts with Cu(II) ions to form reddish brown precipitate of $C u_{2} [F e (C N)_{6}$

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Similar questions

Q. Reagent that can detect any

{F e}^{3 +}, {C o}^{2 +}

{C u}^{2 +}

{N H}_{4} S C N

If the given statement is true enter 1 else enter 0.

K_{4} [F e (C N)_{6}]

can be used to identify

F e^{3 +}, Z n^{2 +}

C d^{2 +}

by forming different colors upon reaction.
If above statement is true, enter 1, else enter 0.

K_{4} [{F e (C N)}_{6}]

can be used to detect some ions out of

{C d}^{2 +}, {C u}^{2 +}, {Z n}^{2 +}, {F e}^{3 +}, {P b}^{2 +}

{B i}^{3 +}

. Excluded ions are :

{F e}^{2 +}

gives blue colour, called Turnbull's blue with

K_{3} [{F e (C N)}_{6}]

{F e}^{3 +}

gives blue colour, called Prussian blue with

K_{4} [{F e (C N)}_{6}]

If the given statement is true enter 1 else enter 0.

Q. Precipitation of

{C d}^{2 +}

{C u}^{2 +}

takes place in presence of dil.

H C l

H_{2} S

If the given statement is true enter 1, else enter 0.

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