A real gas at its critical points has the value of RTc8Pc=0.2L/mol. (Where R is the gas constant). If this gas follows the equation P(V − nb) = nRT at STP, then find the volume (in litres) of the container in which 3 moles of this gas is occupied at STP. (Assume T= 0∘C and P=1 atm at STP)
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Solution
RTc8Pc=R8a27Rb8a27b2=b=0.2L/mol
At STP, 1 mole of an ideal gas occupies 22.4 L.
Since (V-nb) is the volume occupied at an ideal condition. So, for 3 moles, we have, V−3b=22.4×3V=67.2+0.2×3 V=67.8L