Question

A REAL OBJECT IS LOCATED IS LOCATED AT ZERO END OF A METER STICK. A
CONCAVE MIRROR LOCATED AT 100 cm END OF THE METER STICK FORMS AN
IMAGE OF THE OBJECT AT THE 70cm POSITION. A CONVEX MIRROR PLACED AT
THE 60cm POSITION FORMS A FINAL IMAGE AT THE 10 cm POINT WHAT IS THE

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Here},\mathrm{the}\mathrm{image}\mathrm{formed}\mathrm{by}\mathrm{the}\mathrm{concave}\mathrm{mirror}\mathrm{will}\mathrm{act}\mathrm{as}\mathrm{virtual}\mathrm{object}\mathrm{for}\mathrm{convex}\mathrm{mirror}. \\ \mathrm{Thus}, \\ \mathrm{For}\mathrm{convex}\mathrm{mirror}, \\ \mathrm{Object}\mathrm{distance},\mathrm{u}=-(70-60)=-10\mathrm{cm} \\ \mathrm{Image}\mathrm{distance},\mathrm{v}=+(60-10)=+50\mathrm{cm} \\ \mathrm{Using}\mathrm{mirror}\mathrm{formula}, \\ \frac{1}{\mathrm{f}}=\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}} \\ =\frac{1}{(-10)}+\frac{1}{\left(50\right)}=-\frac{4}{50} \\ \mathrm{or}\mathrm{f}=-\frac{50}{4}=-12.5\mathrm{cm} \\ \mathrm{Radius}\mathrm{of}\mathrm{curvature},\mathrm{R}=2\mathrm{f}=2\times 12.5=25\mathrm{cm} \end{gathered}$$