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Question

A real-valued function f(x) satisfies the equation f(xy)=f(x)f(y)f(ax)f(a+y) where 'a' is a constant and f(0) = 1. Then f(2a - x) is equal to

A
-f(x)
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B
f(x)
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C
f(a)+f(a-x)=0
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D
f(-x)
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