A recently discovered isotope of the noble element oganesson (symbol ‘Og’) has electronic configuration 2, 8, 18, 32, 32, 18, 8 and mass number 294.Calculate the number of electrons, protons and neutrons in its atom.

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Solution

From the given electronic configuration we can get the number of electrons.
Sum: (2+8+18+32+32+18+8)=118; hence the number of electrons = 118.
In a neutral atom, the number of protons and number of electrons are equal since the atom is electrically neutral.
Thus number of protons = 118
Given mass number = 294
Mass number = sum of a number of protons and neutrons.
Number of neutrons = mass number - number of protons = (294-118) = 176.

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