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Displacement Current

a rectangle c...

Question

a rectangle coil in a moving coil galvanometer has 50 turns each of length 5 cm and breath 3cm,which is suspended in a radial magnetic field of 0.050wb/m^2. The twist constant of suspension is 15*10^-9Nm/degree. Calculate the current through the coil, which will deflect through 30 degree

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Solution

Dear Student ,
Here in this case the given data is ,
$N = 50 t u r n s, l = 5 c m, b = 3 c m, B = 0 \cdot 05 W b / m^{2}, c = 15 \times 10^{- 9} N m / d e g r e e θ = 30 ° . N o w t h e c u r r e n t t h r o u g h t h e c o i l i s, I = \frac{c}{B N A} θ = \frac{15 \times 10^{- 9}}{0 \cdot 05 \times 50 \times 0 \cdot 05 \times 0 \cdot 03} \times 30 = 1 \cdot 2 \times 10^{- 4} A$

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